Why Ignore the Magnetic Field in a Mass Spectrometer?

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darksyesider
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Homework Statement



Consider a simple mass spectrometer. The magnitude of the electric field between the plates of the velocity selector is 2 500 V/m and the magnetic field in both the velocity selector and the deflection chamber has a magnitude of 0.035 T. Calculate the radius of the path for a singly charged ion with mass m=2.18E-26.




Homework Equations




qE=1/2 mv^2

F = qVxB

The Attempt at a Solution



Solution attached.

Why is the magnetic field ignored for the velocity selector portion??
 
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I don't understand what you mean by ignored as the field strength is used in both calculations.