Why Ignore the Magnetic Field in a Mass Spectrometer?

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SUMMARY

The discussion centers on the operation of a mass spectrometer, specifically addressing the role of electric and magnetic fields in the velocity selector. The electric field strength is specified at 2,500 V/m, while the magnetic field strength is 0.035 T. The calculations involve the equation qE = 1/2 mv² for determining the velocity of ions and the force equation F = qV x B for analyzing the deflection. The magnetic field is considered negligible in the velocity selector due to its specific function in this phase of operation.

PREREQUISITES
  • Understanding of electric fields and their effects on charged particles
  • Familiarity with magnetic fields and their role in mass spectrometry
  • Knowledge of the equations of motion for charged particles in electric and magnetic fields
  • Basic principles of mass spectrometry and ion behavior
NEXT STEPS
  • Study the principles of mass spectrometry, focusing on the role of velocity selectors
  • Learn about the calculations involved in determining ion paths in magnetic fields
  • Explore the effects of varying electric and magnetic field strengths on ion behavior
  • Investigate advanced topics in ion optics and their applications in mass spectrometry
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Students and professionals in physics, particularly those studying mass spectrometry, as well as researchers interested in the behavior of charged particles in electric and magnetic fields.

darksyesider
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Homework Statement



Consider a simple mass spectrometer. The magnitude of the electric field between the plates of the velocity selector is 2 500 V/m and the magnetic field in both the velocity selector and the deflection chamber has a magnitude of 0.035 T. Calculate the radius of the path for a singly charged ion with mass m=2.18E-26.




Homework Equations




qE=1/2 mv^2

F = qVxB

The Attempt at a Solution



Solution attached.

Why is the magnetic field ignored for the velocity selector portion??
 

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I don't understand what you mean by ignored as the field strength is used in both calculations.
 

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