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## Homework Statement

A particle is released from a curve y=ax

^{2}(a=1m

^{-1}) from A on smooth surface. It slides down and flies out from +1 on +tve x . find total horizontal distance D traveled by it .

(see link for image)

http://img59.imageshack.us/img59/6295/sumaj.png

## Homework Equations

Equations of motion

LCE

## The Attempt at a Solution

y1 = 1 * -2

^{2}= 4

y2 = 1 * 1 = 1

I used conservation of energy here.

mg * 4 = m*g*1 + 1/2 m * u

^{2}

Then got u = (60)

^{1/2}

Again applying LCE i get

mg * 4 = 1/2 * m * v

^{2}

From this v = (80)

^{1/2}

Now using v

^{2}= u

^{2}+ 2*g*s

80 = 60 + 20s

s=1 metre

Adding 1 + {1 -(-2)}

= 4 = D

But that's not the actual answer. Any suggestions and can you please point out my mistake?

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