# Distance of alpha particle to gold nucleus

1. Apr 17, 2010

### Linus Pauling

1. The predictions of Rutherford's scattering formula failed to correspond with experimental data when the energy of the incoming alpha particles exceeded 32MeV. This can be explained by the fact that the predictions of the formula apply when the only force involved is the electromagnetic force and will break down if the incoming particles make contact with the nucleus. Use the fact that Rutherford's prediction ceases to be valid for alpha particles with an energy greater than 32MeV to estimate the radius r of the gold nucleus.

2. In the previous problem, I found r = 79e2 / 4pi*epsilon0mpv2

3. 32MeV = 32*106eV = 5.1264*10-12 J

I then did KE = 0.5mpv2, solving for mpv with KE = to the above value. This value is in the denominator of the equation for r given above. Doing the calculation I obtain 1.8*10-15 m, which is incorrect.

2. Apr 18, 2010

### Redbelly98

Staff Emeritus
That doesn't seem right, for two reasons: