Elastic collision between alpha particle and gold Nuclei

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SUMMARY

The discussion focuses on the elastic collision between a 3.94 MeV alpha particle and a gold nucleus at rest, with specific attention to the conservation of momentum and kinetic energy. The alpha particle has a mass of 4.0 u, while the gold nucleus has a mass of 197 u. The key equations involve the conservation of kinetic energy (K1 + K2 = 3.94 MeV) and the conservation of momentum, which must be applied to determine the kinetic energy of both the recoiling nucleus and the rebounding alpha particle. The solution requires calculating the recoil velocities before determining the final kinetic energies.

PREREQUISITES
  • Understanding of elastic collisions in physics
  • Knowledge of conservation of momentum
  • Familiarity with kinetic energy equations
  • Basic concepts of particle physics, specifically alpha particles and nuclear interactions
NEXT STEPS
  • Study the principles of elastic collisions in detail
  • Learn how to apply conservation of momentum in particle interactions
  • Explore kinetic energy calculations in nuclear physics contexts
  • Investigate the properties of alpha particles and their interactions with heavy nuclei
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Students studying physics, particularly those focusing on nuclear physics and particle interactions, as well as educators seeking to explain concepts related to elastic collisions and energy conservation.

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Homework Statement


When an alpha particle collides elastically with a nucleus, the nucleus recoils. Suppose a 3.94 MeV alpha particle has a head-on elastic collision with a gold nucleus that is initially at rest. What is the kinetic energy of (a) the recoiling nucleus and (b) the rebounding alpha particle? The gold nucleus has a mass of 197 u and the alpha has a mass of 4.0 u.

Homework Equations


K1+K2=3.94MeV

The Attempt at a Solution


Since the alpha particle will momentarily stop when the repulsion between the two particles is enough to stop it, the kinetic energy from the particle will all be converted into potential energy so K1f+K2f=3.94Mev. But I'm not sure where to go from here? I feel like I'm missing something simple
 
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You are missing conservation of momentum.

At the point where the alpha particle stops the gold nucleus is already moving, but details of the collision process are not relevant here.
 
as mfb hints...you need first to consider conservation of MOMENTUM to find the recoil velocities...the calculate the KEs
 

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