Distance of Star: Solve Parallax Equation for km & Light Years

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SUMMARY

The discussion revolves around solving the parallax equation for determining the distance to a star in kilometers and light years. The equation used is D=(d/2)/tan(theta/2), with d set at 300 million kilometers and theta at 5 x 10^-5 degrees. The calculated distance is approximately 34 x 10^13 kilometers, which translates to about 27 light years. The participants confirm the calculations and provide insights into the conversion of light years to kilometers.

PREREQUISITES
  • Understanding of the parallax equation and its components
  • Basic knowledge of trigonometric functions, specifically tangent
  • Familiarity with astronomical units, particularly light years
  • Ability to perform calculations with scientific notation
NEXT STEPS
  • Research the concept of parallax in astronomy
  • Learn about the speed of light and its implications for distance measurement
  • Explore the conversion between kilometers and light years in astronomical contexts
  • Study the use of trigonometric functions in real-world applications
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Astronomy students, educators, and anyone interested in understanding distance measurement in space using parallax methods.

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please can somebody help me with this parallax equation:

D=distance to star
theta=angle
using the rule D=(d/2)/tan(theta/2)
when d = 300*10tothe6
and theta = 5*10tothe-5

what is the distance to the star in km and light years?
 
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Okay - assuming that you've given the units in kilometres and degrees...

To get the answers in km you should just be able to plug the numbers into a calculator.

To get the answer in light years you have to first calculate how far a light year is (in km, obviously).

Rather than me just giving you the answer, why don't you have a go, then we can see if our answers agree...

Jess
 
Last edited:
hi there thankyou for your interest in my posting jess

d is in km
theta is in degrees
 
You'll be wanting to hit 'post reply' rather than 'new thread', then :wink:

Oooh look - we've been moved

Jess
 
Last edited:
Originally posted by Jess
You'll be wanting to hit 'post reply' rather than 'new thread', then :wink:

Jess

Presto! The threads are merged.
 
for this answer i get a result of:

343774677078406.6587981892079753

So, is this answer the number of km?

what is this answer in exponential form? ie: 34 * 10tothepower13?

1 light year is 9.467*10tothepower12, so in light years i think the distance will be:
27 light years

Please let me know if i am right
 
Yes, that's the answer in kilometres, and it's the same one that I've got.

34 x 10^13 km is correct as well.

If you take the speed of light to be 300,000 km/s, then a light year is 9.461 x 10^12 km - which looks roughly like what you put.

I get an answer of 36.3 l.y though - you might have typed a digit wrong somewhere, perhaps. Even a back-of-the-envelope type calculation gives an answer of at least 34, if you look closely.

Jess
 
re

thankyou very much jess!
I need the help for some uni coursework.
p.s. I am from edinburgh too!
 
This isn't Astronomy 1Ah or 1Ch work, is it?
 
  • #10
i study at the university of abertay dundee and travel from edinburgh.
My coursework is from "horizons of science 1".
this module is concerned with the big bang, black holes, telecommunications and cosmological phenomena
 
  • #11
Hehe - for a moment there I thought you might be one of my tutees (if that's the right word)

Good luck with the rest of your course...

Jess
 

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