1. The problem statement, all variables and given/known data A 24kg metal ring with 24cm diameter rolls without slipping down a 30 degree incline from a height of 3.4 m. 1) According to the law of conservation of energy what should be the linear speed of the ring at the bottom of the ramp 2) if the ring has a moment of inertia of I=mr^2 what will its linear speed be at the base of the incline? 3) what is the avg linear acc of this ring down the incline? 2. Relevant equations 3. The attempt at a solution For part 1, I got the math down to the square root of 2gh, because I assumed they were just asking for Vfrictionless. I did this through the equation PE=KE(translational) + KE (rotational) from which I got mgh = 1/2mv^2+1/2iw^2 where i=moment of inertia and w=angular velocity. In this case (i) would just be zero, getting me 2gh For part 2 I did the same thing, except I substituted the moment of inertia in for (i) getting the math down to the square root of gh. I had the most difficult time with part three. I wasn't sure where to start so I just worked out a(tangental) = r * angular acceleration. My teacher told me the answer is gsin(x) but I have no idea how he got there.