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lodestar

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## Homework Statement

Two 512Hz tuning forks are placed 3.0 m apart on the bench at the front of a classroom. Each is 2.0 m from a side wall and the room is 7.0 m. The speed of sound is 343 m/s.

b) If the back wall room is 10.0 m away what is the distance from the back corner of the room to the nearest node along the back wall?

## Homework Equations

wavelength = speed/frequency

Path length difference = (n-1/2)λ

## The Attempt at a Solution

The wavelength of sound is found to be 0.67m (wavelength = 343 m/s / 512 Hz).

path length difference = x - (3.5 - x) = 2x - 3.5 m

2x - 3.5m = (n-1/2)λ

x = [(n-1/2)λ + 3.5m]/2

node = 1

x = 1.92 m

I have partial answers from my teacher. The central anti node is 3.5 m from the corner. The first node is 1.12 m from the central antinode. The second node is 3.35 m from the central anti node. The third node is 5.58 m (beyond the corner). The second node is 3.5 - 3.5 = 0.15 m from the corner. I do not understand how to find the distances of these nodes from the central anti node.