Divergence of integral over vacuum energies (Free field)

[soviet1100]

Hi,

The Hamiltonian for the free scalar field, expressed in terms of the creation/annihilation operators, is

H = \int d^{3}p [\omega_p a^{\dagger}_p a_p + \frac{1}{2}\omega_p \delta^{3}(0)] \hspace{3mm}

I thought: \omega_p is a function of p as \omega^{2}_p = |p|^{2} + m^2 and so the dirac delta will sift out the value of \omega_p at p = 0. Could someone tell me why this statement is incorrect? I think I've made some significant conceptual error. Is the first term divergent for infinite p as well?

P.S. wherever p appears above, it is to be taken as the 3-momentum

 

[ShayanJ]

What you expect would happen if the Dirac delta was $\delta^3(p)$. But $\delta^3(0)$ is simply equal to infinity, or more precisely, the volume of whole space, which is a constant.

 

[soviet1100]

What you expect would happen if the Dirac delta was $\delta^3(p)$. But $\delta^3(0)$ is simply equal to infinity, or more precisely, the volume of whole space, which is a constant.

Ah, of course. Thanks, that was silly of me.