Diverging Lens: Find Object Given Real Image & Size

  • Thread starter Thread starter lha08
  • Start date Start date
  • Tags Tags
    Lenses
Click For Summary
SUMMARY

The discussion centers on the optical properties of a diverging lens with a focal length of -20 cm, specifically addressing the conditions under which a real image can be formed. It is established that a diverging lens typically produces virtual, upright, and reduced images; however, a real image can be achieved when a converging beam from another lens is utilized. The magnification formula (M = -(di/do)) is also highlighted, emphasizing the relationship between object distance (do) and image distance (di). The confusion regarding the nature of the image produced by a diverging lens is clarified, confirming that a real image can be larger than the object under specific conditions.

PREREQUISITES
  • Understanding of lens formulas, specifically (1/f)=(1/do)+(1/di)
  • Knowledge of magnification concepts, particularly M=-(di/do)
  • Familiarity with the behavior of diverging lenses and their typical image characteristics
  • Basic principles of optics, including the interaction of converging and diverging beams
NEXT STEPS
  • Study the principles of lens combinations, focusing on retrofocus lens systems
  • Explore the derivation and applications of the lens maker's equation
  • Investigate the effects of varying object distances on image formation in diverging lenses
  • Learn about real and virtual image distinctions in optical systems
USEFUL FOR

Students of optics, physics educators, and anyone interested in the practical applications of lens systems in photography and imaging technology.

lha08
Messages
158
Reaction score
0

Homework Statement


The focal length of a diverging lens is -20 cm. Locate the object, given that the image is real, erect, and 150% of the size of the object.

Homework Equations


(1/f)=(1/do)+(1/di)
M=-(di/do)

The Attempt at a Solution


i'm not really sure how a diverging lens forms a real image (i thought they could only from virtual since most of the images are on the same side) and a size that is larger than the original object. At first, I thought that the image would be inverted (negative magnification) since a virtual image would have a positive magnification (image is upright)...
 
Physics news on Phys.org
For a diverging lens revealed the image of the object is virtual, upright, reduced in size and located on the same side of the lens as the object.

You can form a real image from a diverging lens - but only by feeding it a converging beam from another lens (eg in a retrofocus wide angle camera lens)
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
9
Views
8K
  • · Replies 2 ·
Replies
2
Views
10K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K