- #1

ChiralSuperfields

- 1,276

- 134

- Homework Statement
- Please see below

- Relevant Equations
- Please see below

For this problem,

Distance from objective to object ##šš = 10.6cm##

Distance between the objective and eyepiece ##š· = 34cm##

For (b) I got ##d_I = 26 cm## and ##M_1 = -2.4## which means that firsts image is inverted and real

For (c) I got ##dI' = 35 cm## and ##M_2 = -1.3##. However, I thought ##dI' < 0## since the second image is virtual and inverted from a ray diagram.

For (d)

I got ##M = M_1M_2 = 3.2## which is interesting since the finial image is inverted

Can someone please tell me whether I am correct and how to tell the second image is virtual without drawing a ray diagram?

Many thanks!

Distance from objective to object ##šš = 10.6cm##

Distance between the objective and eyepiece ##š· = 34cm##

For (b) I got ##d_I = 26 cm## and ##M_1 = -2.4## which means that firsts image is inverted and real

For (c) I got ##dI' = 35 cm## and ##M_2 = -1.3##. However, I thought ##dI' < 0## since the second image is virtual and inverted from a ray diagram.

For (d)

I got ##M = M_1M_2 = 3.2## which is interesting since the finial image is inverted

Can someone please tell me whether I am correct and how to tell the second image is virtual without drawing a ray diagram?

Many thanks!

Last edited: