Do All Lower Energy States Exist When n=3 in an Infinite Potential Well?

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Homework Help Overview

The discussion revolves around the concept of energy states in an infinite potential well, specifically focusing on the implications of having a particle described by a wave function that includes multiple terms. The original poster questions whether having the energy state for n=3 necessitates the existence of lower energy states n=2 and n=1.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the relationship between the energy states and the wave function provided, particularly whether the presence of the n=3 state implies the existence of n=1 and n=2 states. Some participants clarify that the wave function indicates a superposition of states.

Discussion Status

The discussion is exploring the implications of the wave function on the possible energy states of the particle. Some guidance has been offered regarding the nature of superposition and the energies that can be measured, but there is no explicit consensus on the interpretation of the energy states involved.

Contextual Notes

The problem is framed within the constraints of quantum mechanics and the specific setup of an infinite potential well, with a focus on the wave function's time dependence and energy measurements.

victoria13
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ok so i have a question on infinite potential wells... if you have the energy state when n=3, does that mean that you have to have the energy state when n=2 and n=1?

Ok basically the Q we are given is:

A particle of mass m is trapped in an infi nitely deep one-dimensional potential well between x = 0 and x = a, and at a time t = 0 is described by the wave function

psi(x,t=0) = sin(pix/a)cos(2pix/a)

(i) What possible values may be found for the energy of the particle?
(ii) What is the expectation (or average) value of the energy of the particle?
(iii) Give an expression showing the time dependence of the wave function, psi(x,t).
[Hint: Use sinAcosB = 1/2(sin(A + B) + sin(A-B))].

so when i use the hint and find the equation in terms of just sin i get

psi(x) = 0.5sin(3pix/a) + 0.5sin(-pix/a)

so does this mean that there is just the 3rd energy state, or the third and first, or all 3?

thanks
 
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The particle is in a superposition of the n=3 state and the n=1 state.
 
so the energies are when n=3 and n=1?
 
Yes, the measurement can only result in energies of states which you have some chance of finding the particle in.
 

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