Do Carmo's book, chap2 Regular surfaces, definition 1.2 -- question

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Discussion Overview

The discussion revolves around the definition of regular surfaces as presented in Do Carmo's book, specifically focusing on the implications of a homeomorphism between sets of different dimensions. Participants express confusion regarding the dimensionality of the sets involved and the validity of the homeomorphism in this context.

Discussion Character

  • Debate/contested

Main Points Raised

  • Some participants question how a homeomorphism can exist between U ⊆ ℝ² and V ∩ S ⊆ ℝ³, citing the difference in dimensions as a fundamental issue.
  • Others reiterate the concern that U and V ∩ S cannot be homeomorphic due to their differing dimensions, with specific references to the dimensionality of ℝ³ and V ∩ S.
  • One participant asserts that U and V ∩ S have the same number of elements and dimensions, suggesting a misunderstanding of the dimensionality involved.
  • Another participant acknowledges a realization regarding the dimensionality of V ∩ S, indicating a shift in understanding but does not clarify the confusion surrounding the homeomorphism.

Areas of Agreement / Disagreement

Participants generally disagree on the dimensionality of V ∩ S and its implications for the homeomorphism, with no consensus reached on the validity of the claims regarding dimensions and homeomorphic relationships.

Contextual Notes

There are unresolved questions regarding the definitions and assumptions related to homeomorphisms and dimensionality, which may affect the clarity of the discussion.

Jianphys17
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On chapter over regular surfaces, In definition 1 point 2. He says that x: U → V∩S is a homeomorphisms, but U⊂ℝ^2 onto V∩S⊂ℝ^3. I am confused, how can it be so!
 
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What's wrong with that?
 
micromass said:
What's wrong with that?
The fact that U ⊆ℝ^2 but V∩S⊆ℝ^3. How can there be a homomorphism between these two spaces, the dimensions are different ! :confused:
 
Jianphys17 said:
The fact that U ⊆ℝ^2 but V∩S⊆ℝ^3. How can there be a homomorphism between these two spaces, the dimensions are different ! :confused:

##\mathbb{R}^3## has dimension 3, but ##V\cap S## has dimension 2##.
 
micromass said:
##\mathbb{R}^3## has dimension 3, but ##V\cap S## has dimension 2##.
Sorry, but U⊂ℝ^2 and p∈S⊂ℝ^3, with neighborhood V⊂ℝ^3. But for homeomorphism definition, |U| ≠ |V∩S| as can be ?
 
##U## and ##V\cap S## have the same number of elements and the same dimension.
 
micromass said:
##U## and ##V\cap S## have the same number of elements and the same dimension.
I had realized that dim(V∩S) = 3.
Anyway thanks for the help.
 
Jianphys17 said:
I had realized that dim(V∩S) = 3.
Anyway thanks for the help.

It doesn't have dimension 3.
 
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