Do Charged Particles Exhibit Stronger Gravitational Fields?

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SUMMARY

Charged subatomic particles do not exhibit a stronger gravitational field than their uncharged counterparts when considering their gravitational influence based solely on mass. Both charged and uncharged particles with identical inertial mass generate the same gravitational field magnitude, as established by the equivalence principle in General Relativity (GR). However, the gravitational field outside a charged particle is more complex due to the presence of an electric field, which contributes to spacetime curvature differently than in uncharged particles. The Reissner-Nordström metric illustrates this distinction, indicating that charged particles can create non-vacuum solutions with non-zero Ricci curvature.

PREREQUISITES
  • Understanding of General Relativity (GR) principles
  • Familiarity with the Reissner-Nordström metric
  • Knowledge of stress-energy tensors in physics
  • Basic concepts of gravitational fields and curvature
NEXT STEPS
  • Study the Reissner-Nordström metric in detail
  • Explore the implications of the equivalence principle in GR
  • Learn about stress-energy tensors and their role in GR
  • Investigate the differences between vacuum and non-vacuum solutions in GR
USEFUL FOR

Physicists, students of theoretical physics, and anyone interested in the interplay between charge and gravity at the subatomic level.

  • #31
TurtleMeister said:
Are you saying that the uncharged particle is not a source of a gravitational field?

I figured that he meant that the field for the charged object is also a source of curvature. But I think he also meant the same for it's mass.
 
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  • #32
When you are computing the energy density of an uncharged object in the stress energy tensor, do you include it's "rest-mass" energy density too?
 
  • #33
quantumfoam said:
When you are computing the energy density of an uncharged object in the stress energy tensor, do you include it's "rest-mass" energy density too?
Yes. That is usually the dominant contributor. It is part of the 0,0 component here:
http://en.wikipedia.org/wiki/Stress–energy_tensor
 
  • #34
Thank you very much:smile:
 
  • #35
Just to be clear, I can't add the stress-energy tensor of a charged subatomic particle in terms of its mass and the stress-energy tensor of the same subatomic particle in terms of its charge?
 
  • #36
quantumfoam said:
Just to be clear, I can't add the stress-energy tensor of a charged subatomic particle in terms of its mass and the stress-energy tensor of the same subatomic particle in terms of its charge?
You can add the stress energy tensors, but the resulting curvature tensors don't add.
 
  • #37
quantumfoam said:
Just to be clear, I can't add the stress-energy tensor of a charged subatomic particle in terms of its mass and the stress-energy tensor of the same subatomic particle in terms of its charge?

Hello

Including charge in the equations of motion opens the door to Lorentz force to be applied on the test particles. This happens to be the case if an electromagnetic stress tensor is added to the gravitational one since the Lorentz force is related with electromagnetic strength tensor F_{{\mu}{\nu}} in GR, as many others may have informed you of. Since it is an additive effect, then of course the field would be slightly stronger though for a subatomic particle like electron, gravity loses to Coulomb strength by 10^{-42} which is quite decent for it to be neglected in any physical scale.

P
 

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