Do I Need Calculus? | ScienceNerd36

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Discussion Overview

The discussion revolves around the necessity of calculus for calculating the instantaneous speed of an object under constant acceleration. Participants explore the relationship between acceleration, velocity, and the mathematical tools required for such calculations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • ScienceNerd36 questions whether calculus is necessary for calculating instantaneous speed at a specific point of acceleration.
  • One participant seeks clarification on the phrase "at a certain point of acceleration," suggesting it refers to evaluating the derivative of velocity at a specific time.
  • Another participant proposes that if acceleration is constant, basic kinematics can be used without calculus to determine speed.
  • A formula is presented: v_{f} = v_{0} + at, indicating a method for calculating final velocity under constant acceleration.

Areas of Agreement / Disagreement

There is no clear consensus; some participants argue that calculus is necessary while others suggest that basic kinematics suffices under constant acceleration.

Contextual Notes

The discussion does not resolve the assumptions regarding the conditions under which calculus may or may not be needed, particularly in varying acceleration scenarios.

ScienceNerd36
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Hello there my fellow atomic aficionados.

I was simply wondering if I need the mathematical tool of calculus under my metaphorical belt, when calculating the instantaneous speed of an object at a certain point of acceleration?

Thanks in advance for any help you may offer.

The Eccentric,
ScienceNerd36.
 
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"at a certain point of acceleration" - i don't really know what you mean, but does that mean at a certain point of the function a(t0) = dv/dt at t0?

then you integrate a(t) to get v(t), and evaluate v(t) at any t0 you want.
 
lolgarithms said:
"at a certain point of acceleration" - i don't really know what you mean, but does that mean at a certain point of the function a(t0) = dv/dt at t0?

then you integrate a(t) to get v(t), and evaluate v(t) at any t0 you want.
I mean if an object was accelerating at 10m/s/s and you took a picture of the object a certain amount of time after the object began its motion, would you need calculus to work out the objects speed at that point.
 
ScienceNerd36 said:
I mean if an object was accelerating at 10m/s/s and you took a picture of the object a certain amount of time after the object began its motion, would you need calculus to work out the objects speed at that point.
If the acceleration is constant you won't need calculus, just basic kinematics.
 
Thanks, you really helped me out.
 
ScienceNerd36 said:
I mean if an object was accelerating at 10m/s/s and you took a picture of the object a certain amount of time after the object began its motion, would you need calculus to work out the objects speed at that point.

[tex]v_{f} = v_{0} + at[/tex]
 

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