You are given how long the ball stays in the air when shot vertically. What is different when it is shot up at an angle of 55 degrees? It will stay in the air a shorter time, but by how much? What is the initial vertical velocity reduced to when the launch angle is 55 degrees?
To @crism7 : Note that @berkeman is not expecting you to find a number for the initial vertical velocity. An algebraic expression will be sufficient. Then see how you can work the given 1.34 s into it.