Do I need to supply a 555 IC with 5V for a temperature intensity meter circuit?

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SUMMARY

The discussion centers on the necessity of supplying a 555 timer IC with 5V in a temperature intensity meter circuit. It is established that each 555 timer requires its own power supply; thus, the second 555 must be powered separately. Additionally, the conversation addresses the proper handling of unused inputs on ICs like the 7447, 74LS393, and 7408, emphasizing the importance of tying unused inputs to avoid floating states, which can lead to unstable outputs.

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  • Understanding of 555 timer configurations (monostable and astable modes)
  • Familiarity with TTL and CMOS logic families
  • Knowledge of basic circuit design principles, including power supply requirements
  • Experience with reading and interpreting IC datasheets
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  • Study the operation of the 555 timer IC in both monostable and astable configurations
  • Learn about proper input handling for TTL and CMOS ICs to prevent floating inputs
  • Review the datasheets for the 7447, 74LS393, and 7408 to understand their pin configurations and requirements
  • Explore best practices for circuit design, focusing on power supply management and signal stability
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I've attached a circuit schematic for the temperaure intensity meter...
R1 is the PTC
the first 555 works as monostable so it triggers second 555 to produce Astable pulses with given frequency depending on the values(R3 and R3 and C4)

anyway i want to ask if i have to supply my second 555 with 5v supplier or not... cause in my circuit I've connect pin 3 of first 555 directly to pin 4 of the second 555 and didn't supply second 555...i've shorted pin 4 with pin 8 ( for the second 555)


want to know your viwpoints, and any suggestion will be appreciated!

thanks in advance!
 

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Each 555 needs its own power supply. Also, I wouldn't mirror the 2nd 555 horizontally on the schematic like that -- it makes it harder to follow.
 
Another question!
I'm so confused about supplying 7447 in my circuit... I know that i have to power it with Vcc on pin 16 and ground the pin 8 but what about the pins such as RB1 and LT (3,5), please help me!

what about some pins for other ICs in this circuit such as LS393 and 7408
any suggestion will be appriciated!



http://www.datasheet4u.com/html/7/4/4/7447_FairchildSemiconductor.pdf.html

http://www.datasheet4u.com/html/7/4/L/74LS393_FairchildSemiconductor.pdf.html

http://www.datasheet4u.com/html/7/4/0/7408_Fairchild.pdf.html

best regards!
 
The other connections can be left unconnected. They look like test connections from their names (zero blanking and lamp test). Unless a pin suggests some type of ENABLE, you can generally ignore extra connections. They are used for debug purposes, but can be useful to connect to a debug/reset circuit.
 
mezarashi said:
The other connections can be left unconnected. They look like test connections from their names (zero blanking and lamp test). Unless a pin suggests some type of ENABLE, you can generally ignore extra connections. They are used for debug purposes, but can be useful to connect to a debug/reset circuit.

what do you mean exactly by debug purposes? do you mean that I wouldn't connect pin3,5 of 7447 unless for debugging/resetting conditions?! :rolleyes:

will the supply of this IC (vCC and GND) be sufficient or i have to connect other pins to have correct output values?

thanks!
 
mezarashi said:
The other connections can be left unconnected.
I disagree. It is very poor design practice to leave unused inputs unconnected. You should instead figure out which direction you want to tie unused inputs to keep them inactive, and either hard tie them straight to that rail, or tie them through a resistor like 10kOhms or so.

The old TTL parts would self-bias unused inputs, so that they generally did not float (but not always). But for sure with modern CMOS logic, if you leave an input floating, it will buzz and float to mid-supply where it causes excessive current drain. Always tie unused inputs inactive.
 
berkeman said:
The old TTL parts would self-bias unused inputs, so that they generally did not float (but not always). But for sure with modern CMOS logic, if you leave an input floating, it will buzz and float to mid-supply where it causes excessive current drain. Always tie unused inputs inactive.

anyway my IC is TTL not CMOS , you think that I should tie unused inputs inactive to insure that it won't get input float...but what do you mean by input floating , i think you meant that the number displayed on 7-seg is not stable and might disappear due to low voltage consumed by it

can you clarify your thought more?! with all my respect!

thanks!
 

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