Do Spherical Waves from Point Sources Transform into Plane Waves?

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SUMMARY

Spherical waves emitted from a point source in a free field transition towards plane waves as they propagate. This transformation results in a decrease in intensity loss with distance, as plane waves maintain a constant wavefront area, unlike spherical waves. The intensity of the waves is inversely proportional to the square of the distance from the source, represented by the equation I = K/r². The discussion confirms that the rate of intensity loss is a rapidly decreasing function of distance, as shown in the provided graph.

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TheEdge
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Hi guys,

Let's assume I have a point source in a free field. Now, correct me if I'm wrong on any of the following points:

  • As the spherical waves spread out from the point source, they will tend towards plane waves.
  • Since planes waves lose less intensity with distance than spherical waves (due to wavefront area not increasing), the rate at which the intensity falls will decrease with distance.
  • A graph will look like the attachment. The black line is for an ideal point source where the waves stay spherical with distance, the blue line for the situation I've described.

Thanks,
Stewart
 

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TheEdge said:
Hi guys,

Let's assume I have a point source in a free field. Now, correct me if I'm wrong on any of the following points:

  • As the spherical waves spread out from the point source, they will tend towards plane waves.
  • Since planes waves lose less intensity with distance than spherical waves (due to wavefront area not increasing), the rate at which the intensity falls will decrease with distance.
  • A graph will look like the attachment. The black line is for an ideal point source where the waves stay spherical with distance, the blue line for the situation I've described.

Thanks,
Stewart
Your black line already accounts for the reduced rate of intensity loss. If there are no energy losses, the intensity (energy per unit area) will be inversely proportional to area, which is proportional to distance^2

I=K/r^2

At some reference distance say 1m, the intensity is Io

Io = K/(1m)^2

So

I/Io = (r/1m)^(-2)

Taking log of both sides

log (I/Io) = -2log(r/1m)

This is what your black line is showing

The rate of intensity loss with increasing distance is the derivative of intensity wrt r

dI/dr = K(-2)/r^3

This is a rapidly decreasing function of r. There is no reason to expect a slower rate.
 

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