Do time-dependent and conservative vector fields exist?

Click For Summary

Discussion Overview

The discussion centers on the nature of conservative vector fields and the implications of time-dependence in such fields. Participants explore whether a time-varying vector field can be classified as conservative, examining definitions, conditions, and examples from physics.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • Some participants assert that a conservative vector field can be expressed as the gradient of a scalar field, which does not account for time variation.
  • One participant mentions that the gradient operates only on spatial variables, implying that time-varying fields cannot be conservative.
  • Another participant suggests there are specific conditions that prevent a time-changing vector field from being conservative, though they are unsure of what those conditions are.
  • A claim is made that a conservative field's line integral is path-independent and that the curl of a conservative field is zero.
  • One participant argues that if a vector field changes over time, the energy associated with a path could vary, contradicting the definition of a conservative field.
  • Another participant discusses the implications of parameterized paths on manifolds, suggesting that time dependence introduces complications that violate the conditions for conservativeness.
  • A participant expresses skepticism about the applicability of manifold concepts, focusing instead on vector calculus.
  • One participant raises a broader question about the nature of certain physical systems, suggesting that they may be incorrectly modeled as conservative despite being time-dependent.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether time-dependent vector fields can be considered conservative. Multiple competing views are presented, with some participants asserting that time dependence inherently disqualifies a field from being conservative, while others explore specific examples and conditions.

Contextual Notes

Some discussions reference advanced concepts such as manifolds and parameterized paths, which may not be familiar to all participants. The conversation also touches on specific physical systems and their modeling, indicating a potential gap in understanding or agreement regarding the implications of time dependence in conservative fields.

fog37
Messages
1,566
Reaction score
108
Hello Forum,

A conservative vector field G(x,y,z) is one that can be expressed as the gradient of a scalar field P(x,y,z).

Could a time-varying vector field like D(x,y,z,t) be a conservative vector field? If not, why not? Can it be conservative (or not) at different time instants?

Thanks!
 
Physics news on Phys.org
The spatial gradient doesn't act on the time variable. Can you reread the definition of "conservative vector field" from your book?.
 
Thanks.

I know that the gradient only operates on the spatial variables. But I also think there are some particular conditions that forbid a time-changing vector field to be conservative...Don't know what they are though...
 
fog37 said:
Thanks.

I know that the gradient only operates on the spatial variables. But I also think there are some particular conditions that forbid a time-changing vector field to be conservative...Don't know what they are though...
What does it mean for a vector field to be conservative? This directly poses strict conditions on a time dependent one.
 
Based on what I know, a conservative field is one whose line integral does not depend on the path but only on the starting and ending points. Hence, a closed path integral will always be zero regardless of the shape and length. I also know that the curl of a conservative field is zero.
 
Yes, and therefore any time dependent path, over a changing field has to add up to zero energy. Especially if you choose the same path and move along at any different, possibly varying speeds. This can only be done if constant in time. The only way out is to let time be part of space, then the question is meaningless.
 
Thanks fresh_42.
hope you have patience. I would like to understand your explanation.
Just to make sure. The paths, in space, are fixed. What changes over time is the vector field. The vector field can be vary in space (i.e. be non homogeneous) but change in time at every spatial point...

I am still not getting it :)
 
fog37 said:
Thanks fresh_42.
hope you have patience. I would like to understand your explanation.
Just to make sure. The paths, in space, are fixed. What changes over time is the vector field. The vector field can be vary in space (i.e. be non homogeneous) but change in time at every spatial point...

I am still not getting it :)
If you consider a special path, it is a parameterized function on the manifold, i.e. ##f: [0,1] \rightarrow M##. But it is not fixed, that you have to move by ##t \mapsto t##. You could as well move by ##t \mapsto t^2##. Now to always get the same path integral, ##0##, it cannot depend on where you are when. So there cannot be a change in time.
 
Thanks. But I don't know about manifolds yet. Sorry. I can handle vector calculus for now.
 
  • #10
fog37 said:
Thanks. But I don't know about manifolds yet. Sorry. I can handle vector calculus for now.
That doesn't matter here. The vector field has to be somewhere. This somewhere is a manifold, e.g. a circle.
If it changes in time, the paths depend on when and where. A varying speed along a path will therefore effect the integral, which is forbidden.
Conservative means: nothing gained and nothing lost on a closed path. If you could gain something at a certain time, and gain nothing the next time you cross the point, then the field cannot be path independent.
 
  • #11
I think to understand exactly what you have meant - have been in situation of late to prove that the natural orbital systems, starting from the Solar (Sun-Earth) - to atomic and galactical ones - are essentially non-conservative, while having been erroneously and totally incorrectly/misleading modeled as conservative (both regarding the alleged time-independent energy and angular momentum, as the zero-valued work over a closed path encompassing center - for introduction, please see
andor send me an e-mail at nedic.slbdn@gmail.com). I am quite positive that the line integral over unit-circle expressed in time-parameterized form would reveal non-zero line integral in the field of "central force" proportional to 1/r^2, whereby r is expressed as time-parameterized Keplerian ellipse, or in other words that the macro-circulation macro-curl/rotor) of such an time-dependent field would turned out to be non-zero ... Keen to cooperate on this?!
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 24 ·
Replies
24
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K