- #1
tgt
- 522
- 2
Does {a^(-2)a, a^(-1)} form a set?
tgt said:Does {a^(-2)a, a^(-1)} form a set?
A set cannot contain repeated elements so if a is a member of a group then
A set is a collection of distinct objects that are considered as a single entity.
The notation a^(-2)a means the product of a^(-2) and a, where a^(-2) is the reciprocal of a^2.
To determine if a set is formed by a^(-2)a and a^(-1), we need to check if the elements in the set satisfy the properties of a set. This means that each element in the set must be unique and there should be a well-defined way to determine if an object belongs to the set or not.
Yes, a set can contain only one element. In this case, a^(-2)a and a^(-1) would form a set with one element, which is a^(-2)a. This is because a^(-2)a is unique and can be easily determined as belonging to the set.
No, the order of elements is not important in a set. This means that a set containing a^(-2)a and a^(-1) is the same as a set containing a^(-1) and a^(-2)a. The only important factor is that each element in the set must be unique.