Does a Blackbody at 200K Emit Twice as Much Radiation?

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SUMMARY

A blackbody at 200K does not emit twice as much radiation as a blackbody at 100K. According to the Stefan-Boltzmann Law, the total power radiated by a blackbody is proportional to the fourth power of its absolute temperature (P ∝ T^4). Therefore, a blackbody at 200K emits 16 times more radiation than one at 100K, as (200^4)/(100^4) equals 16. This relationship is crucial for understanding thermal radiation and energy emission in physics.

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Homework Statement



Does a blackbody at 200K emit twice as much total radiation as when its temperature is 100K?

Homework Equations



N/A

The Attempt at a Solution



I'm not sure, but I think it is yes because if the temperature is doubled, then the energy of the photons will be doubled, therefore it will emit twice as much radiation. Is this correct?
 
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There is a well-known equation that relates radiated power to temperature of a blackbody. It is surely in you class notes or textbook.
 
the only equation in my notes with temperature in it is:
(wavelength) x temperature = 0.002898mK

i don't know how this relates to the question though
 
There should be another equation, involving radiated power. And temperature raised to some integer power. It probably has a Greek lowercase "sigma" in it as well.

If not in your notes, check the textbook.
 

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