Does a Blackbody at 200K Emit Twice as Much Radiation?

  • Thread starter Thread starter clarkandlarry
  • Start date Start date
  • Tags Tags
    Blackbody Radiator
AI Thread Summary
A blackbody at 200K does not emit twice as much radiation as at 100K. The Stefan-Boltzmann Law states that the total power radiated is proportional to the fourth power of the temperature (P ∝ T^4). Therefore, the correct calculation shows that a blackbody at 200K emits 16 times more radiation than at 100K, not double. The discussion highlights the importance of using the correct equations related to blackbody radiation. Understanding these principles is crucial for solving related physics problems.
clarkandlarry
Messages
20
Reaction score
1

Homework Statement



Does a blackbody at 200K emit twice as much total radiation as when its temperature is 100K?

Homework Equations



N/A

The Attempt at a Solution



I'm not sure, but I think it is yes because if the temperature is doubled, then the energy of the photons will be doubled, therefore it will emit twice as much radiation. Is this correct?
 
Physics news on Phys.org
There is a well-known equation that relates radiated power to temperature of a blackbody. It is surely in you class notes or textbook.
 
the only equation in my notes with temperature in it is:
(wavelength) x temperature = 0.002898mK

i don't know how this relates to the question though
 
There should be another equation, involving radiated power. And temperature raised to some integer power. It probably has a Greek lowercase "sigma" in it as well.

If not in your notes, check the textbook.
 
A Full Stack Development Program prepares students to create end to end web applications using front end as well as back-end technologies. The purpose is to get experience in creating user interfaces, managing databases, and conducting server-side activities, resulting in a thorough understanding of how web platforms work. This skill is essential since it allows developers to participate at every step of a project, enhancing critical thinking and productivity. registering in Full Stack...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top