Calculating Quanta Emitted by a Blackbody at 500 C

[Aoiumi]

Homework Statement

The temperature of a blackbody is 500 C. If the intensity of the emitted radiation, 2.0 W/m^2, were due entirely to the most intense frequency component, how many quanta of radiation would be emiteed per second per square meter?

Homework Equations

λmaxT = 2.90 x 10^-3 m K

The Attempt at a Solution

I'm not sure where to begin or how to use intensity.
500 C = 773.15 K

I calculated λmax = 2.90 x 10^-3 m K / 773.15 K = 3750 nm or 3.75 x 10 ^-6 m. I'm not sure where to go from here. Please help. Thank you!

 

[TheAustrian]

A useful relationship to consider is this one:

J=∫^{∞}_{0}J_{λ}(T)dλ

This tells you the total energy radiated per unit time per unit surface area of a black body.

 

[Aoiumi]

Thank you!