Does a compact manifold always have bounded sectional curvature?

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SUMMARY

A compact Riemannian manifold indeed has both lower and upper bounds on sectional curvature. This conclusion is based on the continuity of the curvature tensor across the manifold of tangential 2-planes, which is itself compact. The sectional curvature is defined as the Gauss curvature of these tangential planes, and since the manifold of tangential 2-planes is compact, the sectional curvature is a continuous function. This property ensures that the curvature bounds exist for compact manifolds.

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Sajet
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Sorry if this question seems too trivial for this forum.

A grad student at my university told me that a compact Riemannian manifold always has lower and upper curvature bounds.

Is this really true? The problem seems to be that I don't fully understand the curvature tensor's continuity etc.

What makes me a little skeptical is that I already spent quite a lot of time trying to find a source where this is explicitly stated, without any success. Usually I would expect such a statement as basic as this to appear in lots of books or lecture notes.
 
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Sectional curvature is defined on tangential 2-planes to the manifold. It is just the Gauss curvature of each plane. So it is defined on a different manifold, the manifold of tangential 2 planes, not the original manifold. Each fiber is itself a compact manifold that is diffeomorphic to what is called the Grassmann manifold of 2 planes and the set off all of them across the entire manifold is itself a compact manifold. So you just need to convince yourself that the sectional curvature of is a continuous function on the manifold of tangential 2-planes since this manifold is compact.
 
Thank you!

Yes, I wasn't sure whether the sectional curvature is a continuous function on the unit tangent bundle.
 

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