Does a limit exist on a graph at (-1,0) if the point

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SUMMARY

The discussion centers on the existence of a limit at the point (-1,0) on a graph where a solid dot indicates continuity, but only a right-sided limit exists. It is established that for a limit to exist at a point, both the left-sided and right-sided limits must converge to the same value. In this case, the absence of a left-sided limit indicates that the limit at (-1,0) does not exist, despite the solid dot suggesting that the function is defined at that point. The distinction between solid and open circles is clarified, emphasizing that a solid dot signifies inclusion in the function's domain, not continuity.

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Does a limit exist on a graph at (-1,0) if the point is solid, and has a right sided limit, but there is nothing left of the point?

I understand that if the left sided limit and the right sided limit are different then it doesn't exist, but on my graph it shows a line coming from the right, stopping at (-1,0). where it stops, there is a solid dot indicating it's continuous (I'm assuming, correct me if I'm wrong), but the function stops there. There are no points or lines left of (-1,0)
 
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What's the problem? A right sided limit exists, and a left doesn't. The question of continuity from the left simply makes no sense.
 
The solid dot does not typically indicate continuity at the point (-1,0), rather, it indicates that the function's domain includes the point -1. On the other hand, a circle that is not solid at a point typically indicates that the function either 1) is not defined at that point or 2) has a discontinuity, i.e. you have to look elsewhere to find what the point is defined as in the function. Does that make sense in the context of the graph in your problem?
 

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