Does Air Resistance Cause a Ball to Take Longer Falling Down Than Rising Up?

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Homework Help Overview

The discussion revolves around the effects of air resistance on the time it takes for a ball to rise to its maximum height and fall back down when thrown vertically. Participants are exploring the dynamics of motion under the influence of gravity and air resistance.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to reason that the ball would take longer to fall due to air resistance opposing its motion. Some participants question the validity of this reasoning and clarify the role of air resistance and initial velocity in the context of kinematic equations.

Discussion Status

The discussion is ongoing, with participants providing clarifications and challenging assumptions. There is a focus on understanding the principles of motion and the impact of air resistance, with some guidance offered regarding the use of kinematic equations and the concept of terminal velocity.

Contextual Notes

Participants are navigating assumptions about the effects of air resistance and the nature of acceleration once the ball is thrown. There is also mention of the need for mathematical reasoning, potentially involving calculus, to fully address the question.

yoyo16
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Homework Statement



If a ball is thrown upwards and lands in the same spot, would it take longer to reach max height or drop back down from the max height? Also use air resistance.

Homework Equations





The Attempt at a Solution



I believe that it would take longer for the object to fall back down. I think it is because that when throwing a ball upwards, gravity would be positive and for ex. if a ball was thrown with acceleration of 2m/s^2, you would add two to 9.8 which would help the ball go up faster while when falling down, the ball air resistance would be in the opposite direction causing the ball to fall back slowly. I'm not sure how to explain my answer properly. This is what I understand so far, if I'm not correct can someone please explain this too me.

Thanks,
 
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You are not correct.

First of all let's assume air resistance is a function of velocity and it creates a drag force in the opposite direction of motion.

Second, you can't throw anything with an acceleration once it leaves your hand. You can only accelerate it over the time your hand can continue to exert a force on it. Once it leaves your hand it will only have an initial velocity.

Do you know the kinematic equations of motion?
 
Last edited:
Yes. How would you use that when explaining the answer for this question?
 
yoyo16 said:
Yes. How would you use that when explaining the answer for this question?
I doubt that you will be able to account for your answer mathematically without resorting to the use of caculus. (By the way, air resistance always acts to oppose the motion.)

But perhaps you should ponder an extreme example. (Hint: terminal velocity)
 

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