- #1
jackmell
- 1,807
- 54
Hi,
Consider the algebraic function [itex]w(z)[/itex] given by the expression
[tex]f(z,w)=a_0(z)+a_1(z)w+a_2(z)w^2+\cdots+a_n(z)w^n=0[/tex]
where [itex]f(z,w)[/itex]is irreducible over the rationals, and the coefficients, [itex]a_i(z)[/itex], polynomials with rational coefficients . Let [itex]z_s[/itex] be a point such that [itex]f(z_s,w)=0[/itex] has roots with multiplicty greater than one. Will [itex]w(z)[/itex] always ramify at [itex]z_s[/itex] or can [itex]f(z_s,w)[/itex] have multiple roots and [itex]w(z_s)[/itex] have only regular coverings there?
Edit:
Wasn't hard to find one:
[tex]f(z,w)=(10 z^3/7 -
z^5) + (-3 z^4/5) w + (2 z - 8 z^2/7 + z^3) w^2 + (-5/7) w^3
[/tex]
That one obviously has a multiple root at the origin yet [itex]w(z)[/itex] is reqular there.
Consider the algebraic function [itex]w(z)[/itex] given by the expression
[tex]f(z,w)=a_0(z)+a_1(z)w+a_2(z)w^2+\cdots+a_n(z)w^n=0[/tex]
where [itex]f(z,w)[/itex]is irreducible over the rationals, and the coefficients, [itex]a_i(z)[/itex], polynomials with rational coefficients . Let [itex]z_s[/itex] be a point such that [itex]f(z_s,w)=0[/itex] has roots with multiplicty greater than one. Will [itex]w(z)[/itex] always ramify at [itex]z_s[/itex] or can [itex]f(z_s,w)[/itex] have multiple roots and [itex]w(z_s)[/itex] have only regular coverings there?
Edit:
Wasn't hard to find one:
[tex]f(z,w)=(10 z^3/7 -
z^5) + (-3 z^4/5) w + (2 z - 8 z^2/7 + z^3) w^2 + (-5/7) w^3
[/tex]
That one obviously has a multiple root at the origin yet [itex]w(z)[/itex] is reqular there.
Last edited: