Does continuous acceleration eventually create a black hole

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
6 replies · 1K views
ddesaneis
Messages
12
Reaction score
0
The following equation equates relativistic mass to rest mass
rimg228.gif

http://scienceworld.wolfram.com/physics/RestMass.html

Does the mass caused by high velocity have gravity?
 
Physics news on Phys.org
In general relativity, mass is not the source of gravity, the energy-momentum-tensor is and it also contains information about mass.

You should also read this:
What is relativistic mass and why it is not used much?
Physicists do not talk much about rest mass simply because it is an archaic concept which only tends to confuse the general public.
 
That expression for momentum is correct, but it has nothing to do with the gravitational constant (neither G nor anything derived from it appears).

There's another way of thinking about the question in your original post: right now, even as we speak, you are moving at 99.9999% of the speed of light relative to something somewhere. Are you showing any signs of turning into a black hole?
 
The momentum equation does not include the influence of relativistic mass from gravity, but should.

Nugatory said:
There's another way of thinking about the question in your original post: right now, even as we speak, you are moving at 99.9999% of the speed of light relative to something somewhere. Are you showing any signs of turning into a black hole?

If a GPS satellite returns from orbit to launch site, the relativistic energy within the satellite will correspond to the gravity and velocity (v) of the launch/return site.
https://www.uam.es/personal_pdi/ciencias/jcuevas/Teaching/GPS_relativity.pdf
 
ddesaneis said:
The momentum equation does not include the influence of relativistic mass from gravity, but should.
No it should not. It is a special relativistic equation and there is no gravity in SR. In addition, when you go to GR it becomes a local statement which is still true. Furthermore, relativistic mass is an obsolete concept and you are trying to apply Newtonian gravity to SR rather than going into the actual GR description. This is doomed to fail and to create misunderstandings.