Does Convergence of d(x_n, x) to 0 Imply x_n Approaches x?

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SUMMARY

The discussion centers on the mathematical proof that a sequence \( x_n \) converges to a limit \( x \) if and only if the distance \( d(x_n, x) \) converges to 0. The key equation used is \( |x_n - x| < \epsilon \) for all \( \epsilon > 0 \). Participants clarify that the convergence of \( d(x_n, x) \) to 0 directly implies that the sequence \( x_n \) approaches \( x \) as defined by the standard epsilon-delta definition of convergence.

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BelaTalbot
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Homework Statement


show that x_n converges to x if and only d(x_n, x) converges to 0.


Homework Equations


|x_n - x| < ε for all ε>0




The Attempt at a Solution


well d(x_n,x) converges to 0 if d(x_n,x)<ε
i just don't know how to relate that back to |x_n - x|
 
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