Does cos(1/z) Verify Picard's Big Theorem Near z=0?

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SUMMARY

The discussion centers on verifying Picard's Big Theorem for the function cos(1/z) at the essential singularity z = 0. Participants clarify that cos(w) can take on any complex value when w is complex, particularly when w has a large imaginary part. The theorem states that a function with an essential singularity assumes every complex number, with possibly one exception, in any neighborhood of that singularity. The conversation emphasizes the importance of understanding the behavior of complex functions near singularities, specifically referencing the Casorati-Weierstrass theorem as a useful tool for this analysis.

PREREQUISITES
  • Understanding of Picard's Theorem, specifically the distinction between the little and big theorems.
  • Familiarity with complex analysis concepts, particularly essential singularities.
  • Knowledge of the behavior of trigonometric functions in the complex plane, especially cos(w).
  • Basic understanding of the Casorati-Weierstrass theorem and its implications.
NEXT STEPS
  • Study the Casorati-Weierstrass theorem and its application to complex functions.
  • Explore the implications of Picard's Big Theorem in various complex functions.
  • Investigate the behavior of cos(w) for complex values of w, particularly with large imaginary parts.
  • Review examples of functions with essential singularities, such as e^{1/z}, to deepen understanding.
USEFUL FOR

Mathematicians, students of complex analysis, and anyone interested in the properties of functions with essential singularities and their implications in complex dynamics.

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Homework Statement


Verify Picard's Theorem for cos(1/z) at z = 0

Homework Equations


The theorem:
A function with an essential singularity assumes every complex number, with possibly one exception, as a value in any neighborhood of this singularity

The Attempt at a Solution


I have a solution that I don't understand (from a manual). What the manual does is break out z to get
z = \frac{1}{log(c\pm \sqrt{c^2-1}} for an arbitrary complex constant c. Getting there is trivial enough but I don't get the conclusion.

Values of the logarithm can be chosen to make |z| < \epsilon for any positive \epsilon, so that cos(1/z) achieves the value c in any neighborhood of z = 0.

I understand that you can make z arbitrarily small by choosing a k high enough in the logarithm, but intuitively I'd think cos(z) wouldn't leave [-1, 1] no matter how fast it jumped between them. Intuition be damned, I can't see the reasoning at all. Because I can get a very large input in the cosine function I know the function can output any complex number? How?

Guessing it's something rather silly I'm missing here but there you go.
Any help would be appreciated, cheers.
 
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I think you're missing the fact that \cos{w} does not necessarily sit in the interval [-1,1] when w is complex. For example, if w is pure imaginary, then \cos{w} = \cosh{|w|}.

So the point is that you can use the unboundedness from a large imaginary part of w =1/z plus the phase degree of freedom from the real part of w to get more or less any complex number you want.
 
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You're right, that completely flew me by. Thanks, wasn't that tricky after all.
 
usn7564 said:
How?

First, better define what you mean by Picard's Theorem. He has two, the little one and the big one.

Little: Every entire function that's not a polynomial has an essential singularity at infinity.

Big: A function with an essential singularity achieves every value, with at most one exception, infinitely often in any neighborhood of the singularity.

I think you want the big one.

Any help would be appreciated, cheers.

First do a Wikipedia on Casorati-Weierstrass, study the example for e^{1/z}, then apply that example to your problem.
 

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