Does e^(-infinity + i*w*infinity) equal 0 or 1?
- Thread starter gomes.
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- Exponential Infinity
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SUMMARY
The expression e^(-infinity + i*w*infinity) simplifies to the limit of e^(-x + i*ω*x) as x approaches infinity. This limit can be expressed as e^(-x) * e^(i*ω*x), where e^(-x) approaches 0 and e^(i*ω*x) remains bounded. Therefore, the entire expression converges to 0, confirming that e^(-infinity + i*w*infinity) equals 0.
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