gary350 said:
OH. r from center of earth. r = about 4000 miles at Earth surface. I should have take more physics classes to under stand this. r at Earth surface has a certain amount of gravity how do we know if Earth surface is r2 or r4 of r8?
The equation for gravitational force is
F = GMm/R^2.
M is the mass of one object, m is the mass of the other object, and r is the distance between their centers.
G is a the universal Gravitational constant. It's value depends on the units you are using for R, M&m, and time.
If you use meters for R, Kilograms for M &m, and secs for time, its value is about 6.674 x 10^-11
The answer is in Newtons.
If M is the mass of the Earth(~6 x 10^24 kg), then m is the mass of the other object. This means the answer depends on this. When comparing gravity at different height, it is more convenient to use a equation that doesn't use m.
A = GM/r^2 is such an equation.
Here A is an acceleration. Again, using meters, kilograms and seconds, at the surface of the Earth it is about 9.81 meters/sec^2. This is also called 1g.
Thus, if we measure R in Earth radii, M in Earth masses, and want an answer in gs, we can make G=1
Thus A =1M/(1R)^2 = 1g at the Earth's surface.
Go up to 1R from the surface, and you are 2R from the Earth's center, and
A= 1M/(2R)^2 = 1/4 g.
Gravity is one fourth as much as it is at the surface.
You can also use h for height above the Earth's surface(measured in Earth radii) and then
A = 1/(1+h)^2, .
Again, the answer will be in g