High School Does more energy mean more work?

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More energy correlates with increased work, as demonstrated by the potential energy (PE) of an object at height, like a ball thrown upward. The higher the object, the more work it can do, similar to water in a dam, where increased water height allows for greater energy production through turbines. The energy in systems, such as water cycles, is influenced by solar energy that elevates water to clouds, which eventually replenishes dam levels through rain. However, the total energy remains constant; when a ball reaches maximum height, its potential energy peaks, but the overall energy does not increase. Understanding these principles clarifies the relationship between energy and work in various physical systems.
rudransh verma
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As we always say eat food and rest because tomorrow you have to go to work. When we throw a ball up, it gains a max PE at some height. More the height more energy it has which makes it do more work. Is this right to say?
 
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Yes, the higher the level of water in a dam, the more work the flow of water can do onto the blades of the water turbines-generators, which can produce more electrical energy.

Previously, the Sun energy via evaporation increased the potential energy of the water of rivers, lakes and sea up to the clouds level.
Then, rain replenished the water level in our dam.

Please, see:
https://en.m.wikipedia.org/wiki/Hydroelectricity#Conventional_(dams)
 
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Not exactly. The ball has all of the energy that it's going to have when you release it. Some is Kinetic (velocity) and some is potential (height). When it stops at max height, the potential energy is maximized but the total energy is unchanged.
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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