Does the Absolute Value of this Series Converge? A Scientist's Dilemma

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Homework Help Overview

The discussion revolves around the convergence of the series \(\sum_{n=1}^{\infty}(-1)^{n+1}\frac{\sqrt{n}+1}{n+1}\) and its absolute convergence. Participants are examining the behavior of the series and the implications of the absolute convergence test.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the convergence of the series and the conditions under which it may converge. There are attempts to apply the absolute convergence test, limit comparison, and integral test, with mixed results. Questions arise regarding the validity of the book's claims about convergence.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of convergence. Some guidance has been offered regarding the distinction between absolute and conditional convergence, but no consensus has been reached on the original series' behavior.

Contextual Notes

There is a noted discrepancy between the original poster's findings and the information presented in the textbook, leading to questions about potential errors in the book's assertions regarding convergence.

miglo
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Homework Statement


[tex]\sum_{n=1}^{\infty}(-1)^{n+1}\frac{\sqrt{n}+1}{n+1}[/tex]


Homework Equations


absolute convergence test


The Attempt at a Solution


by book says that the series converges because [tex]\sum_{n=1}^{\infty}\frac{\sqrt{n}+1}{n+1}[/tex] converges
but they don't show how the absolute value of the original series converges, and I've tried showing it myself but i keep getting divergence
i know that as n grows larger and larger the behavior of [tex]\frac{\sqrt{n}+1}{n+1}[/tex] is similar to that of [tex]\frac{\sqrt{n}}{n}[/tex] so i tried using limit comparison and direct comparison with [itex]\frac{1}{n}[/itex] but i keep getting divergence
i tried the integral test but i kept getting divergence also
ive been trying this for far too long so any help would be greatly appreciated
 
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You are correct that the positive term series diverges.
 
but my book says that the original series converges by the absolute convergence test
so wouldn't that mean that [tex]\sum_{n=1}^{\infty}\frac{\sqrt{n}+1}{n+1}[/tex] converges also? or is this an error in the book?
 
miglo said:
but my book says that the original series converges by the absolute convergence test
so wouldn't that mean that [tex]\sum_{n=1}^{\infty}\frac{\sqrt{n}+1}{n+1}[/tex] converges also? or is this an error in the book?

The series is not absolutely convergent. It may be convergent with the alternating signs in which case it would be called "conditionally convergent". (I didn't check that). But the positive term series you are asking about is definitely divergent. You know it is because you correctly checked it.
 
well then ill just check to see if it convergences by the alternating series test
thanks a lot!
 

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