Does the ball clear the net? Please help, thanks in advance?

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The discussion centers on determining whether a tennis ball, hit at a height of 2.0 meters with an initial speed of 22.0 m/s at an angle of 4.5 degrees, clears a net that is 1.0 meter high, located 7.0 meters away. Participants confirm that the ball does clear the net and suggest calculating the vertical and horizontal components of the ball's velocity to find the exact height at the net. The horizontal component of the velocity provides the time taken to reach the net, while the vertical component, combined with gravitational acceleration, allows for the calculation of the ball's height at that distance.

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Does the ball clear the net?? Please help, thanks in advance?

A tennis player hits a ball 2.0m above the ground. The ball leaves his racquet with a speed of 22.0m/s at an angle 4.5 degrees above the horizontal. The horizontal distance to the net is 7.0 m, and the net is 1.0 high.

i know that the ball clears the net .. right..?? i figured that out only by looking at the distance to the net which is 7 and divided it by 2 to get the max. which is 3.5.. and i think that with an angle of 4.5 degrees the ball clears the net.. but i have no idea how to figure out by how much??
 
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reverse said:
A tennis player hits a ball 2.0m above the ground. The ball leaves his racquet with a speed of 22.0m/s at an angle 4.5 degrees above the horizontal. The horizontal distance to the net is 7.0 m, and the net is 1.0 high.

i know that the ball clears the net .. right..?? i figured that out only by looking at the distance to the net which is 7 and divided it by 2 to get the max. which is 3.5.. and i think that with an angle of 4.5 degrees the ball clears the net.. but i have no idea how to figure out by how much??

Yes but you can figure it our more exactly. What is it's vertical Y velocity component? And its X.
The x component gives you the time to net.
The y velocity and that time and gravity give you the height at net.
 

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