Distance between tennis ball and the top of the net

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In this discussion, participants are working through a physics problem involving the trajectory of a tennis ball served at a specific speed and height. They establish the need for two equations: one for horizontal motion (x-direction) and one for vertical motion (y-direction), using the given initial conditions. The correct approach involves calculating the time it takes for the ball to reach the net and then using that time to find the ball's height at the net. For the first scenario, they determine the ball clears the net by 0.66 meters, while the second scenario requires adjusting for an initial downward angle of 5 degrees. The conversation emphasizes the importance of correctly applying the equations of motion and understanding the direction of gravitational acceleration.
  • #31
No I don't, I use the x component in equation 1 and get the time then I plug the time back into equation 2 along with the y component and solve correct?
 
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  • #32
t=12/25.2 = .476s

y=2.5+2.21(.476)-.5(9.8)(.476)^2

y= 2.44

2.44-.9= 1.54m above the net correct?
 
  • #33
Not exactly. I think you got your signs mixed up. It says 5 degrees below the horizontal. What would the components be. Write them out.
 
  • #34
You need to substitute -g for acceleration, since the 'direction' of g is downwards.
 

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