Distance between tennis ball and the top of the net

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SUMMARY

The discussion focuses on calculating the distance between a tennis ball and the top of the net during a serve. The player serves the ball at a speed of 25.3 m/s from a height of 2.5 m, with the net positioned 12 m away and 0.9 m high. The calculations involve using kinematic equations to determine the time of flight and the vertical position of the ball at the net. The final results indicate that when served horizontally, the ball is 0.66 m above the net, while serving at a 5° downward angle results in the ball being 1.54 m above the net.

PREREQUISITES
  • Kinematic equations for projectile motion
  • Understanding of horizontal and vertical motion components
  • Basic trigonometry for angle calculations
  • Acceleration due to gravity (9.8 m/s²)
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  • Study the derivation and application of kinematic equations in projectile motion
  • Learn how to resolve vectors into their components using trigonometric functions
  • Explore the effects of different launch angles on projectile trajectories
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Students studying physics, particularly those focusing on mechanics and projectile motion, as well as tennis coaches and players interested in understanding the physics behind serves.

  • #31
No I don't, I use the x component in equation 1 and get the time then I plug the time back into equation 2 along with the y component and solve correct?
 
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  • #32
t=12/25.2 = .476s

y=2.5+2.21(.476)-.5(9.8)(.476)^2

y= 2.44

2.44-.9= 1.54m above the net correct?
 
  • #33
Not exactly. I think you got your signs mixed up. It says 5 degrees below the horizontal. What would the components be. Write them out.
 
  • #34
You need to substitute -g for acceleration, since the 'direction' of g is downwards.
 

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