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PensNAS

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**1. Homework Statement**

During a tennis match, a player serves the ball at a speed s, with the center of the ball leaving the racquet at angle θ below the horizontal at a height y0. The net is a distance d away and has a height h. When the ball is directly over the net, what is the distance between them? Express your answer in terms of the given variables and the gravitational acceleration g.

**2.Relevant equations**

y=dtanθ-d^2(g/(2(scosθ^2))

**3.The attempt at a solution**

y=dtanθ-d^2(g/(2(scosθ^2))-h

I assumed the equation would give the y at the distance,d. Subtract the height of the net and that would be the distance by which the tennis ball would clear the net. As it turns out, that is not correct. I am a little confused. Any help would be appreciated!