Does the coefficient of restitution depend on the collision "type"?

Click For Summary
The coefficient of restitution does depend on the type of collision being performed, as it varies with the conditions of the impact. In scenarios where two masses collide on a frictionless table, the coefficient can be calculated based on their initial and final velocities. However, if one mass is dropped from a height onto another, the resulting coefficient may differ due to potential breakage or deformation of the objects. While the coefficient may remain approximately constant within a limited range of collision velocities, it is not universally applicable across all collision types. Overall, the nature of the collision significantly influences the coefficient of restitution.
erfz
Probably a very simple question:

Does the coefficient of restitution depend on the collision being performed?

Consider two masses ##m_1## and ##m_2##. They are placed on a frictionless horizontal table and ##m_1## is given an initial velocity, collides 1-dimensionally with ##m_2##, and the coefficient of restitution is calculated from the initial and final velocities.

If instead I had ##m_2## on a table and ##m_1## was dropped from a height ##h_i## onto ##m_2##, and then came up to a height ##h_f##, would the calculated coefficient of restitution be the same here as in the first situation?
 
Physics news on Phys.org
erfz said:
Probably a very simple question:

Does the coefficient of restitution depend on the collision being performed?

Consider two masses ##m_1## and ##m_2##. They are placed on a frictionless horizontal table and ##m_1## is given an initial velocity, collides 1-dimensionally with ##m_2##, and the coefficient of restitution is calculated from the initial and final velocities.

If instead I had ##m_2## on a table and ##m_1## was dropped from a height ##h_i## onto ##m_2##, and then came up to a height ##h_f##, would the calculated coefficient of restitution be the same here as in the first situation?

If you dropped one mass from high enough, then possibly the objects would break apart, rather than bounce off each other.

This suggests to me that the coefficient of restitution for two objects would tend to be approximately constant across a limited range of collision velocities, but in general a single coefficient would not apply across all possible collisions.
 
PeroK said:
If you dropped one mass from high enough, then possibly the objects would break apart, rather than bounce off each other.

This suggests to me that the coefficient of restitution for two objects would tend to be approximately constant across a limited range of collision velocities, but in general a single coefficient would not apply across all possible collisions.
But assuming that they do not break, the coefficient can be applied to both scenarios?
 
erfz said:
But assuming that they do not break, the coefficient can be applied to both scenarios?
In general you may get cracks or permanent deformations, which I suspect will be non-linear in nature.

Have you tried looking online for articles on experiments looking at this?
 
PeroK said:
In general you may get cracks or permanent deformations, which I suspect will be non-linear in nature.

Have you tried looking online for articles on experiments looking at this?
No, but that is a good idea.
Thank you!
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
3K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 30 ·
2
Replies
30
Views
3K
Replies
3
Views
993
  • · Replies 30 ·
2
Replies
30
Views
2K
Replies
2
Views
1K