The Dirac delta function is classified as a distribution rather than a conventional function. It can be conceptualized as the limit of a pulse function. To find its Laplace transform, one can evaluate the limit of the integral of a scaled exponential function as the pulse width approaches zero. This calculation leads to a Laplace transform result of 1. Thus, the Dirac delta function does have a Laplace transform, which is equal to 1.
The δ function isn't actually a function; it is a distribution. It can be thought of informally as the limiting case of a pulse$$
f(t) = \left \{\begin{array}{rl}
h, & 0 < t < \frac 1 h\\
0,& \frac 1 h < t
\end{array}\right.$$ Then, again informally, you can calculate its LaPlace transform by working$$
\lim_{h\rightarrow \infty}\int_0^{\frac 1 h} he^{-st}\, dt$$ You should get an answer of 1.