Does the dirac delta function have a Laplace transform?

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SUMMARY

The Dirac delta function, denoted as δ(t), is classified as a distribution rather than a conventional function. Its Laplace transform can be derived by considering it as the limit of a pulse function defined by f(t) = h for 0 < t < 1/h and 0 otherwise. By applying the limit process, specifically lim(h→∞) ∫(0 to 1/h) he^(-st) dt, the result of the Laplace transform is conclusively 1.

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AdrianZ
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If yes, how can we find it?
 
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AdrianZ said:
If yes, how can we find it?

The δ function isn't actually a function; it is a distribution. It can be thought of informally as the limiting case of a pulse$$
f(t) = \left \{\begin{array}{rl}
h, & 0 < t < \frac 1 h\\
0,& \frac 1 h < t
\end{array}\right.$$ Then, again informally, you can calculate its LaPlace transform by working$$
\lim_{h\rightarrow \infty}\int_0^{\frac 1 h} he^{-st}\, dt$$ You should get an answer of 1.
 
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