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friend
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does the Dirac measure still exist with complex variance?
The Dirac delta function can be rigorously defined as a measure. See
http://en.wikipedia.org/wiki/Dirac_delta_function#As_a_measure
For the gaussian form of the Dirac delta function we have,
[tex]\[
{\rm{\delta (x - x}}_0 ) = \mathop {\lim }\limits_{\Delta \to 0} \frac{1}{{(2\pi \Delta )^{1/2} }}e^{ - (x - x_0 )^2 /(2\Delta )}
\]
[/tex]
with variance [tex]\Delta[/tex].
My question is whether the gaussian from of the Dirac delta is still a measure if the variance is complex. Any insight about this would be appreciated.
The Dirac delta function can be rigorously defined as a measure. See
http://en.wikipedia.org/wiki/Dirac_delta_function#As_a_measure
For the gaussian form of the Dirac delta function we have,
[tex]\[
{\rm{\delta (x - x}}_0 ) = \mathop {\lim }\limits_{\Delta \to 0} \frac{1}{{(2\pi \Delta )^{1/2} }}e^{ - (x - x_0 )^2 /(2\Delta )}
\]
[/tex]
with variance [tex]\Delta[/tex].
My question is whether the gaussian from of the Dirac delta is still a measure if the variance is complex. Any insight about this would be appreciated.
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