Does the heat from the alloy transfer to the water in the setup equation

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SUMMARY

The discussion centers on calculating the specific heat of an alloy using a calorimetry setup involving 25.0 grams of alloy heated to 86.6°C and 61.2 grams of water initially at 19.6°C, which rises to 21.3°C. The formula proposed for the calculation is c = 250*(61.2)/(21.3 * ?), where 250 represents the specific heat capacity of water in J/g°C. The participants seek clarification on the correct application of this formula and the definitions of the variables involved.

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Jurrasic
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This is the problem:
An alloy of mass 25.0 grams was heated to 86.6 C
and then placed in a calorimeter that contained 61.2 grams of water at 19.6 C
The temp of the water rose to 21.3 , determine the specific heat of the alloy in J/gC

Is this the correct way to set it up?

c = 250*(61.2)/(21.3 * ?)
 
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Jurrasic said:
This is the problem:
An alloy of mass 25.0 grams was heated to 86.6 C
and then placed in a calorimeter that contained 61.2 grams of water at 19.6 C
The temp of the water rose to 21.3 , determine the specific heat of the alloy in J/gC

Is this the correct way to set it up?

c = 250*(61.2)/(21.3 * ?)

Can you define each of 250, 61.2 and 21.3 in your result here. My suspicion is that you're wrong, but until I see what you mean by each of these numbers I remain unsure.
 

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