1. The problem statement, all variables and given/known data If a block of 250 grams of lead (specific heat (c) =130) at 315 degrees celsius is placed in a 200 gram aluminum (c=900) calorimeter cup containing 900 grams of water (c=4.1), and the calorimeter and the water are both initially at 15 degrees celsius, what is the equilibrium temperature ? 2. Relevant equations Q=mcΔt Tf=(mct+mct+mct)/(mc+mc+mc) 3. The attempt at a solution Tf=((250x900x315)+(200x900x15)+(900x4.1x15))/((250x130)+(200x900)+(900x4.1) Tf=(70875000+2700000+55350)/(32500+180000+3690) Tf=40.1 I'm not sure if I'm on the right track.