Does the Identity Sin² x + Cos² x = 1 Apply to All Multiples of x?

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    Cos Sin Trigonometry
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Discussion Overview

The discussion centers on the identity ##\sin^2 x + \cos^2 x = 1## and its applicability to multiples of x, specifically examining whether this identity holds for expressions like ##\sin^2 2x + \cos^2 2x##, ##\sin^2 3x + \cos^2 3x##, and ##\sin^2 4x + \cos^2 4x##. The conversation includes both verification of the identity and exploration of related trigonometric identities.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • Some participants assert that the identity ##\sin^2 x + \cos^2 x = 1## applies to all multiples of x, including ##\sin^2 2x + \cos^2 2x##, ##\sin^2 3x + \cos^2 3x##, and ##\sin^2 4x + \cos^2 4x##.
  • One participant emphasizes that the argument can be generalized to ##\sin^2(\text{whatever}) + \cos^2(\text{whatever}) = 1##, provided that the arguments are the same.
  • Questions are raised regarding the relationship between ##\sin^2 2x## and the expression ##\frac{1 - \cos 4x}{2}##, suggesting a connection to double angle identities.

Areas of Agreement / Disagreement

Participants generally agree on the validity of the identity for multiples of x, but there are varying degrees of exploration regarding the implications and related identities, particularly concerning the double angle formulas.

Contextual Notes

Some participants reference specific trigonometric identities without fully resolving the implications or providing detailed proofs, leaving certain assumptions and steps in the discussion open-ended.

basty
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I know that ##\sin^2 x + cos^2 x = 1.##

Is this mean that

##\sin^2 2x + \cos^2 2x = 1##

or

##\sin^2 3x + \cos^2 3x = 1##

or

##\sin^2 4x + \cos^2 4x = 1##

and so on?
 
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Yes.
 
basty said:
I know that ##\sin^2 x + cos^2 x = 1.##

Is this mean that

##\sin^2 2x + \cos^2 2x = 1##

or

##\sin^2 3x + \cos^2 3x = 1##

or

##\sin^2 4x + \cos^2 4x = 1##

and so on?
##sin^2(\text{whatever}) + cos^2(\text{whatever}) = 1##
The "whatever" in both places has to be the same, of course.
 
Does ##\sin^2 2x = \frac{1 - \cos 4x}{2}?##
 
basty said:
Does ##\sin^2 2x = \frac{1 - \cos 4x}{2}?##
##\sin^2(A) = \frac{1 - \cos(2A)}{2}##
If A = 2x, what is 2A?
 

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