Does the Integral of 1/ln(x) from 0 to 1 Diverge or Converge?

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The integral of 1/ln(x) from 0 to 1 is under scrutiny for convergence or divergence. The primary concern is around the behavior of the function as x approaches 1. A comparison function is needed to analyze the integral's behavior in the interval near x=1. The discussion suggests using a linear function related to the tangent of y=ln(x) at x=1 to establish bounds. Ultimately, the goal is to determine if the integral converges to a finite value or diverges to infinity.
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sorry that i do not know the correct english terminology, hope you understand

i need to look into tis integral
\intdx/ln(x) (from 0 to 1)

and say if it comes to a number or to infinity or what, don't necessarily have to gve the answer as a number, can either comapre it to another simpler function or work out the integral.

if F(x)<G(x) and G(x) collects to an actual number than so will F(x), etc
again, hope I am clear and understood
 
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Clearly the only place you could have a problem with convergence is near x=1. Find something to compare with in a small interval near x=1, think about the tangent line to the curve y=ln(x) there.
 
i cannot find such a function of x that is always bigger or always smaller than 1/lnx. could you please show me
 
It doesn't have to be always bigger or always smaller. It only has to be bigger or smaller where it counts. Can you find f(x) so that 1/|f(x)|<1/|ln(x)| only on the interval [0.9,1] and 1/|f(x)| diverges over that interval? Make f a linear function. What is the tangent to y=ln(x) at x=1?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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