Does the inverse of this special matrix have a power series expansion?

  • Context: Graduate 
  • Thread starter Thread starter srz
  • Start date Start date
  • Tags Tags
    Inverse Matrix
Click For Summary

Discussion Overview

The discussion centers on whether the inverse of a specific matrix, expressed as (I + δA)^{-1}, has a power series expansion. The context involves mathematical reasoning related to matrix theory and determinants.

Discussion Character

  • Exploratory, Technical explanation, Mathematical reasoning

Main Points Raised

  • One participant inquires about the existence of a power series expansion for the inverse (I + δA)^{-1}, where δ is a constant and A is a defined matrix.
  • Another participant suggests that a power series expansion may be valid if δ is small enough.
  • A different participant questions the validity of the expression det|I + A| = 1 + trace(A) + det|A|, asking for a general expression for det|I + A| if this is incorrect.
  • One participant proposes testing the formula with A = -I to explore its implications.
  • Another participant notes that there exists a general formula for det(I + A) in terms of traces of powers of A, though it is described as complicated.
  • One participant provides a series expansion for the inverse, stating that it converges if |δA| < 1, and compares the behavior of polynomials and rational functions of matrices to that of single real variables.

Areas of Agreement / Disagreement

The discussion contains multiple competing views regarding the power series expansion and the determinant expression, and it remains unresolved whether the proposed determinant expression holds true.

Contextual Notes

Participants express uncertainty about the conditions under which the power series expansion converges and the validity of the determinant expression, indicating a reliance on specific assumptions about δ and the matrix A.

srz
Messages
3
Reaction score
0
Hi...can anyone please suggest whether the following inverse has a power series expansion
[tex](I+\delta A)^{-1}[/tex]
where [tex]\delta[/tex] is a constant and [tex]A =[/tex]
[tex]\begin{pmatrix} T & T-1 & T-2 &... & 3 & 2 & 1\\ T-1 & T-1 & T-2 & ... & 3 & 2 & 1 \\ .. \\2 & 2 & 2 &... & 2 & 2 & 1 \\ 1 & 1 & 1 & ... & 1 & 1 & 1 \end{pmatrix}[/tex]
Thanks!
 
Physics news on Phys.org
If delta is small enough.
 
Thanks. Is it true that [tex]det|I+A|=1+trace(A)+det|A|[/tex]? If not then is there any general expression for [tex]det|I+A|[/tex]
 
srz, try A = -I in your first formula.

There does exist a general formula for det(I+A) in terms of traces of powers of A, but it's rather complicated. Determinant - Wikipedia has it.
 
Thanks lpetrich.
 
For the inverse, you've got ##(I+\delta A)^{-1}=I-\delta A+(\delta A)^2-(\delta A)^3+\ldots##. It should converge if ##\vert\delta A\vert<1##.

Polynomials and rational functions of a single matrix behave very similarly to the single real variable case.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
8
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
31
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K