The series sum of 1/ln(n+5) from n=1 to infinity diverges. This conclusion is established using the comparison test, where it is shown that 1/ln(n+5) is greater than 1/n for n starting from 2. The divergence holds true even when the comparison starts at n=2, as the behavior of the series from n=1 does not affect the overall divergence. Therefore, the proof remains valid despite the initial index of summation.
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cloveryeah said:Homework Statement
summation n from 1 to inf, 1/ln(n+5) converge or diverge
Homework Equations
The Attempt at a Solution
1/ln(n+5) > 1/n (from n=2 to inf)
and i proved that it diverges by comparison test, am i correct?
i am thinking that as my prove is n from 2 to inf not from 1 to inf
can i still use this prove?