Does the Series \(\sum_{n=1}^\infty \frac{1}{n\sqrt[n]{n}}\) Converge?

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SUMMARY

The series \(\sum_{n=1}^\infty \frac{1}{n\sqrt[n]{n}}\) does not converge. The term \(\sqrt[n]{n}\) approaches 1 as \(n\) approaches infinity, leading to the conclusion that the series behaves similarly to the harmonic series. Since the harmonic series diverges, the original series also diverges. This conclusion is supported by analyzing the behavior of the first \(k\) partial sums in relation to the harmonic series.

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steviet
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[tex]\sum_{n=1}^\infty \frac{1}{n\sqrt[n]{n}}\][/tex]

Does this series converge?
 
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No it doesn't, because [tex]\sqrt[n]{n}}[/tex] approaches 1 as n approaches infinity. Hence if we were to the the first k partial sums of the series in your post, and the harmonic series, the difference would approach a constant as k approached infinity. Since the harmonic series diverges, so does this one.
 

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