Does the torque increase or decrease as the angle increase?

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Homework Help Overview

The discussion revolves around a simple pendulum problem involving torque calculations related to the angle of displacement from the vertical. The original poster presents a scenario with a mass and a string, seeking to understand how torque behaves as the angle increases.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are examining the relationship between the angle of the pendulum and the resulting torque, with some questioning the correctness of the original poster's calculations and assumptions regarding the torque equation.

Discussion Status

There is an ongoing examination of the torque calculation, with participants providing feedback on the original poster's approach. Some have pointed out potential inaccuracies in the application of the torque formula and the interpretation of the angle's effect on torque.

Contextual Notes

Participants are discussing the implications of using the correct length and angle in the torque equation, highlighting the need for clarity on the definitions and assumptions involved in the problem setup.

mandy9008
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Homework Statement


A simple pendulum consists of a small object of mass 2.4 kg hanging at the end of a 2.0 m long light string that is connected to a pivot point.
(a) Calculate the magnitude of the torque (due to the force of gravity) about this pivot point when the string makes a 3.0° angle with the vertical.
(b) Does the torque increase or decrease as the angle increase?
(c)Explain your answer.

Homework Equations


A=Lsinө
τ=Amgsinө

The Attempt at a Solution


a. A=2.0m sin 3.0
A= 0.105m

τ=0.105m (2.4kg)(9.8m/s2)sin 3.0
τ= 0.129 Nm

b. angle will increase
c. Since angle increases, sin of the angle also increases
 
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What's the question here?
 


the answer in bold is incorrect
 


You have an extra sin in there.
You're correct that the equation for torque is
[tex] \tau = \vec{r} \times \vec{F} = mgl sin\theta[/tex]
So it's based on the cross product of the displacement vector 'r' (the vector from the pivot point to the mass) and the force vector 'F' (which is the force due to gravity). The angle between those vectors is theta.
But you need to use 'l' as the full length, and the sin of theta takes into account the angle.
 

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