Does this make any sense at all? Surface Area/Integral

  • Thread starter Thread starter flyingpig
  • Start date Start date
  • Tags Tags
    Surface
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 1K views
flyingpig
Messages
2,574
Reaction score
1

Homework Statement

Let's say I have a parametric surface [tex]\mathbf{r}(u,v) = <x(u,v),y(u,v),z(u,v)>[/tex]

Let's say I have to solve some surface integral

[tex]\iint f(x,y,z)\;dS[/tex]

Can I do this differential?

[tex]dS = |\mathbf{r_u} \times \mathbf{r_v}|dA[/tex]

also, has anyone noticed how small LaTeX has gotten on PF?
 
Physics news on Phys.org
flyingpig said:

Homework Statement




Let's say I have a parametric surface [tex]\mathbf{r}(u,v) = <x(u,v),y(u,v),z(u,v)>[/tex]

Let's say I have to solve some surface integral

[tex]\iint f(x,y,z)\;dS[/tex]

Can I do this differential?

[tex]dS = |\mathbf{r_u} \times \mathbf{r_v}|dA[/tex]

also, has anyone noticed how small LaTeX has gotten on PF?

What do you mean 'can I do it'? If the r_u and r_v are partial derivatives and dA means du*dv, then that's an expression for dS alright.
 
flyingpig said:
Let's say I have a parametric surface [tex]\mathbf{r}(u,v) = <x(u,v),y(u,v),z(u,v)>[/tex]

Let's say I have to solve some surface integral

[tex]\iint f(x,y,z)\;dS[/tex]

Can I do this differential?

[tex]dS = |\mathbf{r_u} \times \mathbf{r_v}|dA[/tex]


absolutely