Does this series have an analytical solution?

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The analytical solution to the infinite series \(\sum\limits_{n = 0}^\infty {\exp \left( { - An} \right)}\) is definitively identified as \(\frac{1}{1 - e^{-A}}\), which converges for \(A > 0\). This series is recognized as a geometric series, where \(e^{-An} = (e^{-A})^{n}\). The discussion confirms the convergence criteria and the transformation of the exponential term into a geometric format.

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FrankDrebon
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Hi all,

Can anyone show how I'd work out the analytical solution to an infinite series of this form:

[tex]\sum\limits_{n = 0}^\infty {\exp \left( { - An} \right)}[/tex]

Thanks in advance,

F
 
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FrankDrebon said:
Hi all,

Can anyone show how I'd work out the analytical solution to an infinite series of this form:

[tex]\sum\limits_{n = 0}^\infty {\exp \left( { - An} \right)}[/tex]

Thanks in advance,

F

It's just a geometric series Frank

[tex]\sum\limits_{n = 0}^\infty {\exp \left( { - An} \right)} = \frac{1}{1 - e^{-A}}[/tex]

Converges for A>0
 
Just to fill in a detail:
[tex]e^{-An}=(e^{-A})^{n}[/tex]
For all A and n.

As uart said, this is a geometric series.
 

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