Does Time Flow for a Photon in the Context of Time-Space?

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SUMMARY

The discussion centers on the concept of time flow for a photon, specifically addressing the equation Δt=γ Δt' and its implications as velocity approaches the speed of light (c). It is established that as velocity approaches c, the Lorentz factor γ approaches infinity, leading to the conclusion that Δt' (the time experienced by a photon) is effectively zero. The conversation also clarifies that while time and distance appear to "shrink" to zero from a photon's perspective, this does not imply that photons are stationary or "frozen" in time, as the mathematical limits involved cannot be physically realized.

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Kinny
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Hi everybody]Since we see light, from the equation Δt=γ Δt' , Δt' (the Δtime in a photon) should be zero, cause γ→+∞ for v→c and Δt is a discrete number (if we actually see photons). So, I thought the time in a photon doesn't flow, but my Physic friend said it's wrong..? In the frequently asked question, it's written that the time "shrinks to zero", isn't that the same to say it doesn't flow in a photon?
Also, there's written that the distance shrinks to zero, but isn't suppose Δs'→+∞ ? Otherwise, for Δs=Δs' / γ , wouldn't we see the photons like "freeze", like not moving??
* γ = 1/ √(1-v^2 /c^2)
thanks for the answers...and sorry if I'm not approaching this in a very "elegant" way (i'm doing engineering XD
 
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You're only quoting a very small portion of the FAQ and thus taking it out of context. Do you understand that when mathematicians speak of a limit, they mean something that you can approach to as closely as you want, but you're not allowed to actually get to? So the FAQ is saying that it's meaningless to talk about what happens when you get to the limit because you can't get there.
 

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